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背景:

简单公式 求改成大智慧L2能用的

[日期:2020-01-19] 来源:  作者: [字体: ]

编写要求:

股票网解答:

 网友求助:

抄底: PSY.PSY<=25,STICK,COLORYELLOW,LINETHICK2;
STICKLINE(CROSS(PSY.PSY,30),0,1,2,0);


WZ1:=MA(CLOSE,5);
WZ2:=MA(CLOSE,10);
WZ3:=MA(CLOSE,20);
WZ5:=MA(CLOSE,60);
JD5:ATAN((WZ1/REF(WZ1,1)-1)*100)*57.3,NODRAW;
JD10:ATAN((WZ2/REF(WZ2,1)-1)*100)*57.3,NODRAW;
JD20:ATAN((WZ3/REF(WZ3,1)-1)*100)*57.3,NODRAW;
JD60:ATAN((WZ5/REF(WZ5,1)-1)*100)*57.3,NODRAW;

 

简单公式 求改成大智慧L2能用的

解答如下:
PSY:COUNT(CLOSE>REF(CLOSE,1),12)/12*100,LINETHICK0;
抄底: PSY<=25,STICK,COLORYELLOW,LINETHICK2;
STICKLINE(CROSS(PSY,30),0,1,8,0),COLOR00FFFF;
WZ1:=MA(CLOSE,5);
WZ2:=MA(CLOSE,10);
WZ3:=MA(CLOSE,20);
WZ5:=MA(CLOSE,60);
JD5:ATAN((WZ1/REF(WZ1,1)-1)*100)*57.3,LINETHICK0;
JD10:ATAN((WZ2/REF(WZ2,1)-1)*100)*57.3,LINETHICK0;
JD20:ATAN((WZ3/REF(WZ3,1)-1)*100)*57.3,LINETHICK0;
JD60:ATAN((WZ5/REF(WZ5,1)-1)*100)*57.3,LINETHICK0;
CROSS(JD60,10) AND JD10>20,LINETHICK2,COLORWHITE;
 

 

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