J:=(3*EMA(RSV,3)-2*EMA(EMA(RSV,3),3));
KDJ1:=REF(COUNT(J<REF(J,1),5)>=3,1) AND REF(J,1)<20;
KDJ2:=J>REF(J,1);
刨1:=IF(CROSS(0.9,1/VOL*1000>0.01 AND "KDJ.J"<0),1,0);
问2:=IF(FILTER(KDJ1 AND KDJ2,3),1,0);
刨根问底:刨1 AND 问2;
[日期:2020-01-18] | 来源: 作者: | [字体:大 中 小] |