MACD公式中出现底背离时的选股公式
2020-1-20 1:24:18

编写要求:


股票网解答:
网友求助:
DIFF : EMA(CLOSE,SHORT) - EMA(CLOSE,LONG);

DEA  : EMA(DIFF,M);

MACD=2*(DIFF-DEA);

Zero : 0;

gj:=MAX(C,O);

STICKLINE(MACD>0 AND MACD>=REF(MACD,1),0,MACD,2,0),color0000ff;

STICKLINE(MACD>0 AND MACD<REF(MACD,1),0,MACD,2,0),colorffff00;

STICKLINE(MACD<0 AND MACD>=REF(MACD,1),0,MACD,2,0),colorff00ff;

STICKLINE(MACD<0 AND MACD<REF(MACD,1),0,MACD,2,0),color00ff00;

L4:=LLV(gj,4);

jl:=(HHV(diff,55)-LLV(diff,55))/5;

gt:=dea>REF(dea,1) AND REF(dea,1)<REF(dea,2);

A1:=BARSLAST(REF(gt,1));

底背离:=REF(L4,A1+1)>CLOSE AND diff>REF(diff,A1+1) AND gt;

DRAWLINE(A1=0,DEA,底背离,REF(DEA,A1),0),colorred,LINETHICK2;

DRAWLINE(底背离,DEA,底背离,REF(DEA,A1),0),colorred,LINETHICK2;

DRAWTEXT(底背离,REF(DEA,A1)*1.18,' 底背离'),COLORFF00FF;

H4:=HHV(gj,4);

gt2:=dea<REF(dea,1) AND REF(dea,1)>REF(dea,2);

A2:=BARSLAST(REF(gt2,1));

顶背离:= REF(H4,A2+1)<H4 AND  diff<REF(diff,A2+1) AND gt2;

DRAWLINE(A2=0  ,DEA,顶背离,REF(DEA,A2),0),colorgreen,LINETHICK2;

DRAWLINE(顶背离,DEA,顶背离,REF(DEA,A2),0),colorgreen,LINETHICK2;

DRAWTEXT(顶背离,REF(DEA,A2)*1.18,' 顶背离'),colorgreen;
解答如下:
DIFF:=EMA(CLOSE,12) - EMA(CLOSE,26);

DEA:=EMA(DIFF,9);

GT:=DEA>REF(DEA,1) AND REF(DEA,1)<REF(DEA,2);

A1:=BARSLAST(REF(GT,1));

GJ:=MAX(C,O);

L4:=LLV(GJ,4);

底背离:REF(L4,A1+1)>CLOSE AND DIFF>REF(DIFF,A1+1) AND GT;




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